A googol (10100) is a massive number: one followed by one-hundred zeros; 100100 is almost unimaginably large: one followed by two-hundred zeros. Despite their size, the sum of the digits in each number is only 1.
Considering natural numbers of the form, ab, where a, b < 100, what is the maximum digital sum?
So, let’s do nested loops, both going 1 to 100. Inside the inner loop, calculate a^b (or i^j in this case). Then loop through the digits of that value, adding them up. Keep track of which is the largest value this produces.
Running time about 3 seconds in Python:
import time
tStart = time.time()
maxsum = 0
for i in range(100):
for j in range(100):
num = i ** j
total = 0
for k in str(num):
total += int(k)
if total > maxsum:
maxsum = total
print(maxsum)
print("time:" + str(time.time() - tStart))




